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201140220043 = 728734317149
BaseRepresentation
bin1011101101010011100…
…1000011000010001011
3201020011210210212100101
42323110321003002023
511243413344020133
6232222540550231
720350304442460
oct2732471030213
9636153725311
10201140220043
1178337457414
1232b95552377
1315c766128a9
149a416cd667
15537360237d
hex2ed4e4308b

201140220043 has 4 divisors (see below), whose sum is σ = 229874537200. Its totient is φ = 172405902888.

The previous prime is 201140220013. The next prime is 201140220109. The reversal of 201140220043 is 340022041102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 201140220043 - 213 = 201140211851 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 201140220043.

It is not an unprimeable number, because it can be changed into a prime (201140220013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14367158568 + ... + 14367158581.

It is an arithmetic number, because the mean of its divisors is an integer number (57468634300).

Almost surely, 2201140220043 is an apocalyptic number.

201140220043 is a deficient number, since it is larger than the sum of its proper divisors (28734317157).

201140220043 is an equidigital number, since it uses as much as digits as its factorization.

201140220043 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 28734317156.

The product of its (nonzero) digits is 384, while the sum is 19.

Adding to 201140220043 its reverse (340022041102), we get a palindrome (541162261145).

The spelling of 201140220043 in words is "two hundred one billion, one hundred forty million, two hundred twenty thousand, forty-three".

Divisors: 1 7 28734317149 201140220043