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2012011102011 = 3670670367337
BaseRepresentation
bin11101010001110101001…
…101001111111100111011
321010100100111212001102010
4131101311031033330323
5230431044320231021
64140145524341003
7265235340121131
oct35216515177473
97110314761363
102012011102011
1170631a8a5579
12285b36544763
13117968ab5221
146d54bb5b751
153750c6e2976
hex1d47534ff3b

2012011102011 has 4 divisors (see below), whose sum is σ = 2682681469352. Its totient is φ = 1341340734672.

The previous prime is 2012011101953. The next prime is 2012011102051. The reversal of 2012011102011 is 1102011102102.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 2012011102011 - 222 = 2012006907707 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2012011102051) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 335335183666 + ... + 335335183671.

It is an arithmetic number, because the mean of its divisors is an integer number (670670367338).

Almost surely, 22012011102011 is an apocalyptic number.

2012011102011 is a deficient number, since it is larger than the sum of its proper divisors (670670367341).

2012011102011 is an equidigital number, since it uses as much as digits as its factorization.

2012011102011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 670670367340.

The product of its (nonzero) digits is 8, while the sum is 12.

Adding to 2012011102011 its reverse (1102011102102), we get a palindrome (3114022204113).

Subtracting from 2012011102011 its reverse (1102011102102), we obtain a palindrome (909999999909).

The spelling of 2012011102011 in words is "two trillion, twelve billion, eleven million, one hundred two thousand, eleven".

Divisors: 1 3 670670367337 2012011102011