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2012011515131 = 8590812342051
BaseRepresentation
bin11101010001110101001…
…110110100110011111011
321010100100112122001002212
4131101311032310303323
5230431044421441011
64140145541245335
7265235343461432
oct35216516646373
97110315561085
102012011515131
117063200579a2
12285b3670384b
13117968bcb287
146d54bc28119
153750c77508b
hex1d4753b4cfb

2012011515131 has 4 divisors (see below), whose sum is σ = 2012014716264. Its totient is φ = 2012008314000.

The previous prime is 2012011515109. The next prime is 2012011515169. The reversal of 2012011515131 is 1315151102102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2012011515131 is a prime.

It is a super-2 number, since 2×20120115151312 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2012011515097 and 2012011515106.

It is not an unprimeable number, because it can be changed into a prime (2012011515931) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 311945 + ... + 2030106.

It is an arithmetic number, because the mean of its divisors is an integer number (503003679066).

Almost surely, 22012011515131 is an apocalyptic number.

2012011515131 is a deficient number, since it is larger than the sum of its proper divisors (3201133).

2012011515131 is an equidigital number, since it uses as much as digits as its factorization.

2012011515131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3201132.

The product of its (nonzero) digits is 300, while the sum is 23.

Adding to 2012011515131 its reverse (1315151102102), we get a palindrome (3327162617233).

The spelling of 2012011515131 in words is "two trillion, twelve billion, eleven million, five hundred fifteen thousand, one hundred thirty-one".

Divisors: 1 859081 2342051 2012011515131