Base | Representation |
---|---|
bin | 11101010001110111000… |
… | …000100100111001010011 |
3 | 21010100102121202000101120 |
4 | 131101313000210321103 |
5 | 230431130040144410 |
6 | 4140152524333323 |
7 | 265236155105103 |
oct | 35216700447123 |
9 | 7110377660346 |
10 | 2012041334355 |
11 | 706335974588 |
12 | 285b446a4243 |
13 | 11797213bba0 |
14 | 6d551b8b203 |
15 | 375101b5570 |
hex | 1d477024e53 |
2012041334355 has 16 divisors (see below), whose sum is σ = 3466901991840. Its totient is φ = 990543426048.
The previous prime is 2012041334339. The next prime is 2012041334389. The reversal of 2012041334355 is 5534331402102.
It is not a de Polignac number, because 2012041334355 - 24 = 2012041334339 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5159080150 + ... + 5159080539.
It is an arithmetic number, because the mean of its divisors is an integer number (216681374490).
Almost surely, 22012041334355 is an apocalyptic number.
2012041334355 is a deficient number, since it is larger than the sum of its proper divisors (1454860657485).
2012041334355 is a wasteful number, since it uses less digits than its factorization.
2012041334355 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10318160710.
The product of its (nonzero) digits is 43200, while the sum is 33.
Adding to 2012041334355 its reverse (5534331402102), we get a palindrome (7546372736457).
The spelling of 2012041334355 in words is "two trillion, twelve billion, forty-one million, three hundred thirty-four thousand, three hundred fifty-five".
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