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201211102033 = 255178875383
BaseRepresentation
bin1011101101100100011…
…1011100001101010001
3201020100202012001011021
42323121013130031101
511244040020231113
6232233552115441
720352125101504
oct2733107341521
9636322161137
10201211102033
1178373470077
1232bb5235b81
1315c881cc9b6
149a4aca113b
15537995448d
hex2ed91dc351

201211102033 has 4 divisors (see below), whose sum is σ = 201289979968. Its totient is φ = 201132224100.

The previous prime is 201211101991. The next prime is 201211102049. The reversal of 201211102033 is 330201112102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-201211102033 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 201211101998 and 201211102016.

It is not an unprimeable number, because it can be changed into a prime (201211102933) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 39435141 + ... + 39440242.

It is an arithmetic number, because the mean of its divisors is an integer number (50322494992).

Almost surely, 2201211102033 is an apocalyptic number.

It is an amenable number.

201211102033 is a deficient number, since it is larger than the sum of its proper divisors (78877935).

201211102033 is an equidigital number, since it uses as much as digits as its factorization.

201211102033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 78877934.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 201211102033 its reverse (330201112102), we get a palindrome (531412214135).

The spelling of 201211102033 in words is "two hundred one billion, two hundred eleven million, one hundred two thousand, thirty-three".

Divisors: 1 2551 78875383 201211102033