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201214551115 = 5211190724693
BaseRepresentation
bin1011101101100101010…
…0100110010001001011
3201020100222200021102001
42323121110212101023
511244041411113430
6232234154051431
720352166315234
oct2733124462113
9636328607361
10201214551115
1178375406456
1232bb6419b77
1315c88b39886
149a4b51c08b
155379dd63ca
hex2ed952644b

201214551115 has 8 divisors (see below), whose sum is σ = 242601810768. Its totient is φ = 160208741280.

The previous prime is 201214551079. The next prime is 201214551149. The reversal of 201214551115 is 511155412102.

201214551115 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 201214551115 - 27 = 201214550987 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 95361292 + ... + 95363401.

It is an arithmetic number, because the mean of its divisors is an integer number (30325226346).

Almost surely, 2201214551115 is an apocalyptic number.

201214551115 is a deficient number, since it is larger than the sum of its proper divisors (41387259653).

201214551115 is a wasteful number, since it uses less digits than its factorization.

201214551115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 190724909.

The product of its (nonzero) digits is 2000, while the sum is 28.

Adding to 201214551115 its reverse (511155412102), we get a palindrome (712369963217).

The spelling of 201214551115 in words is "two hundred one billion, two hundred fourteen million, five hundred fifty-one thousand, one hundred fifteen".

Divisors: 1 5 211 1055 190724693 953623465 40242910223 201214551115