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2012200322113 = 11579173780147
BaseRepresentation
bin11101010010000000011…
…111000100010001000001
321010100211200220102121001
4131102000133010101001
5230431441240301423
64140220404132001
7265243125350212
oct35220037042101
97110750812531
102012200322113
11706407695423
12285b89997001
13117999066997
146d568d35409
153751e11ccad
hex1d4807c4441

2012200322113 has 4 divisors (see below), whose sum is σ = 2012374113840. Its totient is φ = 2012026530388.

The previous prime is 2012200322107. The next prime is 2012200322137. The reversal of 2012200322113 is 3112230022102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2012200322113 - 29 = 2012200321601 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2012200322183) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 86878495 + ... + 86901652.

It is an arithmetic number, because the mean of its divisors is an integer number (503093528460).

Almost surely, 22012200322113 is an apocalyptic number.

It is an amenable number.

2012200322113 is a deficient number, since it is larger than the sum of its proper divisors (173791727).

2012200322113 is a wasteful number, since it uses less digits than its factorization.

2012200322113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 173791726.

The product of its (nonzero) digits is 288, while the sum is 19.

Adding to 2012200322113 its reverse (3112230022102), we get a palindrome (5124430344215).

The spelling of 2012200322113 in words is "two trillion, twelve billion, two hundred million, three hundred twenty-two thousand, one hundred thirteen".

Divisors: 1 11579 173780147 2012200322113