Base | Representation |
---|---|
bin | 11101010010000001111… |
… | …101110010100110011001 |
3 | 21010100220102121222202120 |
4 | 131102001331302212121 |
5 | 230432014114402213 |
6 | 4140223052251453 |
7 | 265243546410555 |
oct | 35220175624631 |
9 | 7110812558676 |
10 | 2012225153433 |
11 | 70641a705580 |
12 | 285b96170b89 |
13 | 1179a124c181 |
14 | 6d56c35a865 |
15 | 375213c5423 |
hex | 1d481f72999 |
2012225153433 has 16 divisors (see below), whose sum is σ = 2926919688192. Its totient is φ = 1219510922000.
The previous prime is 2012225153369. The next prime is 2012225153447. The reversal of 2012225153433 is 3343515222102.
It is a cyclic number.
It is not a de Polignac number, because 2012225153433 - 26 = 2012225153369 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (33).
It is a junction number, because it is equal to n+sod(n) for n = 2012225153394 and 2012225153403.
It is not an unprimeable number, because it can be changed into a prime (2012225152433) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1766728 + ... + 2673158.
It is an arithmetic number, because the mean of its divisors is an integer number (182932480512).
Almost surely, 22012225153433 is an apocalyptic number.
It is an amenable number.
2012225153433 is a deficient number, since it is larger than the sum of its proper divisors (914694534759).
2012225153433 is a wasteful number, since it uses less digits than its factorization.
2012225153433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 973716.
The product of its (nonzero) digits is 43200, while the sum is 33.
The spelling of 2012225153433 in words is "two trillion, twelve billion, two hundred twenty-five million, one hundred fifty-three thousand, four hundred thirty-three".
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