Base | Representation |
---|---|
bin | 1001001001101010000000… |
… | …10001001001110010010001 |
3 | 2122020201222110200221002020 |
4 | 10210311000101021302101 |
5 | 10114143401001120423 |
6 | 110444213435242053 |
7 | 4144560461652414 |
oct | 444650021116221 |
9 | 78221873627066 |
10 | 20123000020113 |
11 | 64591309a6721 |
12 | 230bb7bba9329 |
13 | b2c78ab8b823 |
14 | 4d7d5bbb3b7b |
15 | 24d6a33d64e3 |
hex | 124d40449c91 |
20123000020113 has 8 divisors (see below), whose sum is σ = 26830687416576. Its totient is φ = 13415322985200.
The previous prime is 20123000019937. The next prime is 20123000020169. The reversal of 20123000020113 is 31102000032102.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a de Polignac number, because none of the positive numbers 2k-20123000020113 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20123000020092 and 20123000020101.
It is not an unprimeable number, because it can be changed into a prime (20123000020183) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6303328 + ... + 8943038.
It is an arithmetic number, because the mean of its divisors is an integer number (3353835927072).
Almost surely, 220123000020113 is an apocalyptic number.
It is an amenable number.
20123000020113 is a deficient number, since it is larger than the sum of its proper divisors (6707687396463).
20123000020113 is a wasteful number, since it uses less digits than its factorization.
20123000020113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5180775.
The product of its (nonzero) digits is 72, while the sum is 15.
Adding to 20123000020113 its reverse (31102000032102), we get a palindrome (51225000052215).
The spelling of 20123000020113 in words is "twenty trillion, one hundred twenty-three billion, twenty thousand, one hundred thirteen".
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