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201234040131 = 367078013377
BaseRepresentation
bin1011101101101001111…
…0111100010101000011
3201020102100100102022110
42323122132330111003
511244111403241011
6232240131510403
720352524055435
oct2733236742503
9636370312273
10201234040131
1178385407883
1233000a58403
1315c8cba1537
149a4dd52655
15537b985ba6
hex2eda7bc543

201234040131 has 4 divisors (see below), whose sum is σ = 268312053512. Its totient is φ = 134156026752.

The previous prime is 201234040129. The next prime is 201234040153. The reversal of 201234040131 is 131040432102.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 201234040131 - 21 = 201234040129 is a prime.

It is a super-2 number, since 2×2012340401312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 201234040098 and 201234040107.

It is not an unprimeable number, because it can be changed into a prime (201234040171) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33539006686 + ... + 33539006691.

It is an arithmetic number, because the mean of its divisors is an integer number (67078013378).

Almost surely, 2201234040131 is an apocalyptic number.

201234040131 is a deficient number, since it is larger than the sum of its proper divisors (67078013381).

201234040131 is an equidigital number, since it uses as much as digits as its factorization.

201234040131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 67078013380.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 201234040131 its reverse (131040432102), we get a palindrome (332274472233).

The spelling of 201234040131 in words is "two hundred one billion, two hundred thirty-four million, forty thousand, one hundred thirty-one".

Divisors: 1 3 67078013377 201234040131