Search a number
-
+
20124115131 = 36708038377
BaseRepresentation
bin10010101111011111…
…011010000010111011
31220221111001222012110
4102233133122002323
5312203233141011
613124521343403
71311460104411
oct225737320273
956844058173
1020124115131
1185975a160a
123a97637b63
131b89312943
14d8c9932b1
157cbad5ba6
hex4af7da0bb

20124115131 has 4 divisors (see below), whose sum is σ = 26832153512. Its totient is φ = 13416076752.

The previous prime is 20124115103. The next prime is 20124115133. The reversal of 20124115131 is 13151142102.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 20124115131 - 213 = 20124106939 is a prime.

It is a super-2 number, since 2×201241151312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 20124115098 and 20124115107.

It is not an unprimeable number, because it can be changed into a prime (20124115133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3354019186 + ... + 3354019191.

It is an arithmetic number, because the mean of its divisors is an integer number (6708038378).

Almost surely, 220124115131 is an apocalyptic number.

20124115131 is a deficient number, since it is larger than the sum of its proper divisors (6708038381).

20124115131 is an equidigital number, since it uses as much as digits as its factorization.

20124115131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6708038380.

The product of its (nonzero) digits is 240, while the sum is 21.

Adding to 20124115131 its reverse (13151142102), we get a palindrome (33275257233).

The spelling of 20124115131 in words is "twenty billion, one hundred twenty-four million, one hundred fifteen thousand, one hundred thirty-one".

Divisors: 1 3 6708038377 20124115131