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2012430013003 = 17118378236059
BaseRepresentation
bin11101010010001110001…
…011010001001001001011
321010101102201002221021001
4131102032023101021023
5230432424040404003
64140255251155431
7265251614605024
oct35221613211113
97111381087231
102012430013003
11706515307603
122860328a5b77
13117a04818357
146d58b645c4b
153753438e61d
hex1d48e2d124b

2012430013003 has 4 divisors (see below), whose sum is σ = 2130808249080. Its totient is φ = 1894051776928.

The previous prime is 2012430012979. The next prime is 2012430013021. The reversal of 2012430013003 is 3003100342102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2012430013003 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2012430013063) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 59189118013 + ... + 59189118046.

It is an arithmetic number, because the mean of its divisors is an integer number (532702062270).

Almost surely, 22012430013003 is an apocalyptic number.

2012430013003 is a deficient number, since it is larger than the sum of its proper divisors (118378236077).

2012430013003 is a wasteful number, since it uses less digits than its factorization.

2012430013003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 118378236076.

The product of its (nonzero) digits is 432, while the sum is 19.

Adding to 2012430013003 its reverse (3003100342102), we get a palindrome (5015530355105).

The spelling of 2012430013003 in words is "two trillion, twelve billion, four hundred thirty million, thirteen thousand, three".

Divisors: 1 17 118378236059 2012430013003