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201253124003 = 1711838419059
BaseRepresentation
bin1011101101101110011…
…1101111011110100011
3201020110200020222110112
42323123213233132203
511244131244432003
6232242052521535
720353145220521
oct2733347573643
9636420228415
10201253124003
1178395161878
12330073202ab
1315c93b23979
149a526bd311
15537d4a53d8
hex2edb9ef7a3

201253124003 has 4 divisors (see below), whose sum is σ = 213091543080. Its totient is φ = 189414704928.

The previous prime is 201253123997. The next prime is 201253124047. The reversal of 201253124003 is 300421352102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 201253124003 - 222 = 201248929699 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 201253124003.

It is not an unprimeable number, because it can be changed into a prime (201253124903) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5919209513 + ... + 5919209546.

It is an arithmetic number, because the mean of its divisors is an integer number (53272885770).

Almost surely, 2201253124003 is an apocalyptic number.

201253124003 is a deficient number, since it is larger than the sum of its proper divisors (11838419077).

201253124003 is a wasteful number, since it uses less digits than its factorization.

201253124003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11838419076.

The product of its (nonzero) digits is 1440, while the sum is 23.

Adding to 201253124003 its reverse (300421352102), we get a palindrome (501674476105).

The spelling of 201253124003 in words is "two hundred one billion, two hundred fifty-three million, one hundred twenty-four thousand, three".

Divisors: 1 17 11838419059 201253124003