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20130000001 = 110503182167
BaseRepresentation
bin10010101111110101…
…110110110010000001
31220221220010221201121
4102233311312302001
5312211240000001
613125251432241
71311561114436
oct225765666201
956856127647
1020130000001
11859a950a41
123a995b5681
131b8a5c3407
14d8d685b8d
157cc3996a1
hex4afd76c81

20130000001 has 4 divisors (see below), whose sum is σ = 20130292672. Its totient is φ = 20129707332.

The previous prime is 20129999983. The next prime is 20130000029. The reversal of 20130000001 is 10000003102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-20130000001 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (20130000041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19420 + ... + 201586.

It is an arithmetic number, because the mean of its divisors is an integer number (5032573168).

Almost surely, 220130000001 is an apocalyptic number.

It is an amenable number.

20130000001 is a deficient number, since it is larger than the sum of its proper divisors (292671).

20130000001 is a wasteful number, since it uses less digits than its factorization.

20130000001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 292670.

The product of its (nonzero) digits is 6, while the sum is 7.

Adding to 20130000001 its reverse (10000003102), we get a palindrome (30130003103).

The spelling of 20130000001 in words is "twenty billion, one hundred thirty million, one", and thus it is an aban number.

Divisors: 1 110503 182167 20130000001