Base | Representation |
---|---|
bin | 11101010010110000001… |
… | …001101000100110010011 |
3 | 21010102220102122210022210 |
4 | 131102300021220212103 |
5 | 230440111000311011 |
6 | 4140432012203203 |
7 | 265302005524155 |
oct | 35226011504623 |
9 | 7112812583283 |
10 | 2013000010131 |
11 | 706788032910 |
12 | 286171769503 |
13 | 117a9593a866 |
14 | 6d60321cad5 |
15 | 375694326a6 |
hex | 1d4b0268993 |
2013000010131 has 8 divisors (see below), whose sum is σ = 2928000014784. Its totient is φ = 1220000006120.
The previous prime is 2013000010093. The next prime is 2013000010159. The reversal of 2013000010131 is 1310100003102.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 2013000010131 - 210 = 2013000009107 is a prime.
It is a super-4 number, since 4×20130000101314 (a number of 50 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is not an unprimeable number, because it can be changed into a prime (2013000010171) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 30500000121 + ... + 30500000186.
It is an arithmetic number, because the mean of its divisors is an integer number (366000001848).
Almost surely, 22013000010131 is an apocalyptic number.
2013000010131 is a deficient number, since it is larger than the sum of its proper divisors (915000004653).
2013000010131 is a wasteful number, since it uses less digits than its factorization.
2013000010131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 61000000321.
The product of its (nonzero) digits is 18, while the sum is 12.
Adding to 2013000010131 its reverse (1310100003102), we get a palindrome (3323100013233).
The spelling of 2013000010131 in words is "two trillion, thirteen billion, ten thousand, one hundred thirty-one".
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