Search a number
-
+
20130012011 = 29059692729
BaseRepresentation
bin10010101111110101…
…111001101101101011
31220221220011120012102
4102233311321231223
5312211240341021
613125252004015
71311561164444
oct225765715553
956856146172
1020130012011
11859a959a6a
123a9960060b
131b8a5c8a15
14d8d68a2cb
157cc39d00b
hex4afd79b6b

20130012011 has 4 divisors (see below), whose sum is σ = 20130733800. Its totient is φ = 20129290224.

The previous prime is 20130011917. The next prime is 20130012053. The reversal of 20130012011 is 11021003102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 20130012011 - 222 = 20125817707 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 20130011983 and 20130012001.

It is not an unprimeable number, because it can be changed into a prime (20130012311) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 317306 + ... + 375423.

It is an arithmetic number, because the mean of its divisors is an integer number (5032683450).

Almost surely, 220130012011 is an apocalyptic number.

20130012011 is a deficient number, since it is larger than the sum of its proper divisors (721789).

20130012011 is an equidigital number, since it uses as much as digits as its factorization.

20130012011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 721788.

The product of its (nonzero) digits is 12, while the sum is 11.

Adding to 20130012011 its reverse (11021003102), we get a palindrome (31151015113).

The spelling of 20130012011 in words is "twenty billion, one hundred thirty million, twelve thousand, eleven".

Divisors: 1 29059 692729 20130012011