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20130103131 = 36710034377
BaseRepresentation
bin10010101111110110…
…001111111101011011
31220221220100012012020
4102233312033331123
5312211301300011
613125253545523
71311562024215
oct225766177533
956856305166
1020130103131
11859aa11476
123a996452a3
131b8a62b338
14d8d6b15b5
157cc3ba006
hex4afd8ff5b

20130103131 has 4 divisors (see below), whose sum is σ = 26840137512. Its totient is φ = 13420068752.

The previous prime is 20130103127. The next prime is 20130103139. The reversal of 20130103131 is 13130103102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 20130103131 - 22 = 20130103127 is a prime.

It is a super-2 number, since 2×201301031312 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 20130103131.

It is not an unprimeable number, because it can be changed into a prime (20130103139) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3355017186 + ... + 3355017191.

It is an arithmetic number, because the mean of its divisors is an integer number (6710034378).

Almost surely, 220130103131 is an apocalyptic number.

20130103131 is a deficient number, since it is larger than the sum of its proper divisors (6710034381).

20130103131 is an equidigital number, since it uses as much as digits as its factorization.

20130103131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6710034380.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 20130103131 its reverse (13130103102), we get a palindrome (33260206233).

The spelling of 20130103131 in words is "twenty billion, one hundred thirty million, one hundred three thousand, one hundred thirty-one".

Divisors: 1 3 6710034377 20130103131