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201301100201 = 683294730747
BaseRepresentation
bin1011101101111001111…
…0110000011010101001
3201020121000112102102202
42323132132300122221
511244231040201301
6232250525105545
720354300056025
oct2733636603251
9636530472382
10201301100201
117840a250023
123301b3b82b5
1315ca0a50b56
149a58c0b385
1553827d066b
hex2ede7b06a9

201301100201 has 4 divisors (see below), whose sum is σ = 201595831632. Its totient is φ = 201006368772.

The previous prime is 201301100123. The next prime is 201301100267. The reversal of 201301100201 is 102001103102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-201301100201 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (201301102201) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 147364691 + ... + 147366056.

It is an arithmetic number, because the mean of its divisors is an integer number (50398957908).

Almost surely, 2201301100201 is an apocalyptic number.

It is an amenable number.

201301100201 is a deficient number, since it is larger than the sum of its proper divisors (294731431).

201301100201 is an equidigital number, since it uses as much as digits as its factorization.

201301100201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 294731430.

The product of its (nonzero) digits is 12, while the sum is 11.

Adding to 201301100201 its reverse (102001103102), we get a palindrome (303302203303).

The spelling of 201301100201 in words is "two hundred one billion, three hundred one million, one hundred thousand, two hundred one".

Divisors: 1 683 294730747 201301100201