2013011011331 has 4 divisors (see below), whose sum is σ = 2023441120392. Its totient is φ = 2002580902272.

The previous prime is 2013011011313. The next prime is 2013011011357. The reversal of 2013011011331 is 1331101103102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2013011011331 - 2¹⁴ = 2013010994947 is a prime.

It is a super-3 number, since 3×2013011011331³ (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2013011011931) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5215054241 + ... + 5215054626.

It is an arithmetic number, because the mean of its divisors is an integer number (505860280098).

Almost surely, 2^{2013011011331} is an apocalyptic number.

2013011011331 is a deficient number, since it is larger than the sum of its proper divisors (10430109061).

2013011011331 is a wasteful number, since it uses less digits than its factorization.

2013011011331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10430109060.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 2013011011331 its reverse (1331101103102), we get a palindrome (3344112114433).

The spelling of 2013011011331 in words is "two trillion, thirteen billion, eleven million, eleven thousand, three hundred thirty-one".