Base | Representation |
---|---|
bin | 10010101111110110… |
… | …010001101100000011 |
3 | 1220221220100112220110 |
4 | 102233312101230003 |
5 | 312211302011321 |
6 | 13125254042403 |
7 | 1311562053651 |
oct | 225766215403 |
9 | 56856315813 |
10 | 20130110211 |
11 | 859aa16822 |
12 | 3a99649403 |
13 | 1b8a631623 |
14 | d8d6b3dd1 |
15 | 7cc3bc176 |
hex | 4afd91b03 |
20130110211 has 4 divisors (see below), whose sum is σ = 26840146952. Its totient is φ = 13420073472.
The previous prime is 20130110201. The next prime is 20130110219. The reversal of 20130110211 is 11201103102.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 20130110211 - 25 = 20130110179 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (20130110219) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3355018366 + ... + 3355018371.
It is an arithmetic number, because the mean of its divisors is an integer number (6710036738).
Almost surely, 220130110211 is an apocalyptic number.
20130110211 is a deficient number, since it is larger than the sum of its proper divisors (6710036741).
20130110211 is an equidigital number, since it uses as much as digits as its factorization.
20130110211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6710036740.
The product of its (nonzero) digits is 12, while the sum is 12.
Adding to 20130110211 its reverse (11201103102), we get a palindrome (31331213313).
The spelling of 20130110211 in words is "twenty billion, one hundred thirty million, one hundred ten thousand, two hundred eleven".
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