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201303130019 = 637931557161
BaseRepresentation
bin1011101101111010011…
…0011111111110100011
3201020121011100112211012
42323132212133332203
511244232100130034
6232251040411135
720354323241615
oct2733646377643
9636534315735
10201303130019
1178410407062
1233020016aab
1315ca12b1a24
149a591b8db5
155382a81cce
hex2ede99ffa3

201303130019 has 4 divisors (see below), whose sum is σ = 201334693560. Its totient is φ = 201271566480.

The previous prime is 201303129991. The next prime is 201303130027. The reversal of 201303130019 is 910031303102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 201303130019 - 212 = 201303125923 is a prime.

It is a super-2 number, since 2×2013031300192 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 201303129976 and 201303130003.

It is not an unprimeable number, because it can be changed into a prime (201303130079) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15772202 + ... + 15784959.

It is an arithmetic number, because the mean of its divisors is an integer number (50333673390).

Almost surely, 2201303130019 is an apocalyptic number.

201303130019 is a deficient number, since it is larger than the sum of its proper divisors (31563541).

201303130019 is an equidigital number, since it uses as much as digits as its factorization.

201303130019 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 31563540.

The product of its (nonzero) digits is 486, while the sum is 23.

The spelling of 201303130019 in words is "two hundred one billion, three hundred three million, one hundred thirty thousand, nineteen".

Divisors: 1 6379 31557161 201303130019