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2013041430555 = 35711890179747
BaseRepresentation
bin11101010010110010100…
…111101001000000011011
321010110000022121011110120
4131102302213221000123
5230440202101234210
64140440052044323
7265303020556341
oct35226247510033
97113008534416
102013041430555
117067a9453671
122861836036a3
13117aa13b0a9c
146d608921991
153756cdb5270
hex1d4b29e901b

2013041430555 has 16 divisors (see below), whose sum is σ = 3266230604544. Its totient is φ = 1058500657760.

The previous prime is 2013041430539. The next prime is 2013041430559. The reversal of 2013041430555 is 5550341403102.

It is not a de Polignac number, because 2013041430555 - 24 = 2013041430539 is a prime.

It is a super-2 number, since 2×20130414305552 (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (2013041430559) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 945088809 + ... + 945090938.

It is an arithmetic number, because the mean of its divisors is an integer number (204139412784).

Almost surely, 22013041430555 is an apocalyptic number.

2013041430555 is a deficient number, since it is larger than the sum of its proper divisors (1253189173989).

2013041430555 is a wasteful number, since it uses less digits than its factorization.

2013041430555 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1890179826.

The product of its (nonzero) digits is 36000, while the sum is 33.

Adding to 2013041430555 its reverse (5550341403102), we get a palindrome (7563382833657).

The spelling of 2013041430555 in words is "two trillion, thirteen billion, forty-one million, four hundred thirty thousand, five hundred fifty-five".

Divisors: 1 3 5 15 71 213 355 1065 1890179747 5670539241 9450898735 28352696205 134202762037 402608286111 671013810185 2013041430555