Base | Representation |
---|---|
bin | 11101010010110010101… |
… | …110111100010010000001 |
3 | 21010110000110012101220220 |
4 | 131102302232330102001 |
5 | 230440203044011023 |
6 | 4140440201053253 |
7 | 265303043050365 |
oct | 35226256742201 |
9 | 7113013171826 |
10 | 2013043344513 |
11 | 7067aa540653 |
12 | 286184187229 |
13 | 117aa1900cc6 |
14 | 6d608c9d2a5 |
15 | 3756d1423e3 |
hex | 1d4b2bbc481 |
2013043344513 has 4 divisors (see below), whose sum is σ = 2684057792688. Its totient is φ = 1342028896340.
The previous prime is 2013043344497. The next prime is 2013043344527. The reversal of 2013043344513 is 3154433403102.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 2013043344513 - 24 = 2013043344497 is a prime.
It is not an unprimeable number, because it can be changed into a prime (2013043344553) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 335507224083 + ... + 335507224088.
It is an arithmetic number, because the mean of its divisors is an integer number (671014448172).
Almost surely, 22013043344513 is an apocalyptic number.
It is an amenable number.
2013043344513 is a deficient number, since it is larger than the sum of its proper divisors (671014448175).
2013043344513 is an equidigital number, since it uses as much as digits as its factorization.
2013043344513 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 671014448174.
The product of its (nonzero) digits is 51840, while the sum is 33.
Adding to 2013043344513 its reverse (3154433403102), we get a palindrome (5167476747615).
The spelling of 2013043344513 in words is "two trillion, thirteen billion, forty-three million, three hundred forty-four thousand, five hundred thirteen".
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