Base | Representation |
---|---|
bin | 1011101101111010101… |
… | …1011001000011111011 |
3 | 201020121020202200221012 |
4 | 2323132223121003323 |
5 | 11244232412144121 |
6 | 232251124104135 |
7 | 20354340162434 |
oct | 2733653310373 |
9 | 636536680835 |
10 | 201304412411 |
11 | 78411102593 |
12 | 3302053504b |
13 | 15ca164063b |
14 | 9a5943048b |
15 | 5382c36c5b |
hex | 2edead90fb |
201304412411 has 8 divisors (see below), whose sum is σ = 210294689280. Its totient is φ = 192333961512.
The previous prime is 201304412399. The next prime is 201304412417. The reversal of 201304412411 is 114214403102.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 201304412411 - 210 = 201304411387 is a prime.
It is a super-2 number, since 2×2013044124112 (a number of 23 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (23).
It is not an unprimeable number, because it can be changed into a prime (201304412417) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4935731 + ... + 4976348.
It is an arithmetic number, because the mean of its divisors is an integer number (26286836160).
Almost surely, 2201304412411 is an apocalyptic number.
201304412411 is a deficient number, since it is larger than the sum of its proper divisors (8990276869).
201304412411 is an equidigital number, since it uses as much as digits as its factorization.
201304412411 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9912985.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 201304412411 its reverse (114214403102), we get a palindrome (315518815513).
The spelling of 201304412411 in words is "two hundred one billion, three hundred four million, four hundred twelve thousand, four hundred eleven".
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