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2013044442043 = 6584330573401
BaseRepresentation
bin11101010010110010110…
…011001000001110111011
321010110000112021011110011
4131102302303020032323
5230440203334121133
64140440240402351
7265303055301235
oct35226263101673
97113015234404
102013044442043
117068001201a8
122861846163b7
13117aa1bc672b
146d6090a7255
153756d2ac6cd
hex1d4b2cc83bb

2013044442043 has 4 divisors (see below), whose sum is σ = 2013075081288. Its totient is φ = 2013013802800.

The previous prime is 2013044442041. The next prime is 2013044442137. The reversal of 2013044442043 is 3402444403102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2013044442043 - 21 = 2013044442041 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2013044441996 and 2013044442014.

It is not an unprimeable number, because it can be changed into a prime (2013044442041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15220858 + ... + 15352543.

It is an arithmetic number, because the mean of its divisors is an integer number (503268770322).

Almost surely, 22013044442043 is an apocalyptic number.

2013044442043 is a deficient number, since it is larger than the sum of its proper divisors (30639245).

2013044442043 is an equidigital number, since it uses as much as digits as its factorization.

2013044442043 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 30639244.

The product of its (nonzero) digits is 36864, while the sum is 31.

Adding to 2013044442043 its reverse (3402444403102), we get a palindrome (5415488845145).

The spelling of 2013044442043 in words is "two trillion, thirteen billion, forty-four million, four hundred forty-two thousand, forty-three".

Divisors: 1 65843 30573401 2013044442043