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20131000103113 = 611766511868183
BaseRepresentation
bin1001001001111000111010…
…00111000011000011001001
32122021111122000021020211121
410210330131013003003021
510114311242011244423
6110452015340555241
74145262643356514
oct444743507030311
978244560236747
1020131000103113
116461566820469
122311633252b21
13b30464430653
144d84ba49dd7b
1524d9c08eb45d
hex124f1d1c30c9

20131000103113 has 8 divisors (see below), whose sum is σ = 20461143278016. Its totient is φ = 19800861018000.

The previous prime is 20131000103057. The next prime is 20131000103117. The reversal of 20131000103113 is 31130100013102.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 20131000103113 - 29 = 20131000102601 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (20131000103117) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9841620 + ... + 11709802.

It is an arithmetic number, because the mean of its divisors is an integer number (2557642909752).

Almost surely, 220131000103113 is an apocalyptic number.

It is an amenable number.

20131000103113 is a deficient number, since it is larger than the sum of its proper divisors (330143174903).

20131000103113 is a wasteful number, since it uses less digits than its factorization.

20131000103113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2044895.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 20131000103113 its reverse (31130100013102), we get a palindrome (51261100116215).

The spelling of 20131000103113 in words is "twenty trillion, one hundred thirty-one billion, one hundred three thousand, one hundred thirteen".

Divisors: 1 61 176651 1868183 10775711 113959163 330016395133 20131000103113