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2013100130131 = 2791721282741
BaseRepresentation
bin11101010010110110000…
…111100011111101010011
321010110011102001102010221
4131102312013203331103
5230440312113131011
64140445550133511
7265304332526206
oct35226607437523
97113142042127
102013100130131
117068295a6512
1228619b1b1297
13117ab05c3b6c
146d61264193d
153757310c971
hex1d4b61e3f53

2013100130131 has 4 divisors (see below), whose sum is σ = 2013821415664. Its totient is φ = 2012378844600.

The previous prime is 2013100130077. The next prime is 2013100130137. The reversal of 2013100130131 is 1310310013102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2013100130131 - 223 = 2013091741523 is a prime.

It is a super-2 number, since 2×20131001301312 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2013100130137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 360638580 + ... + 360644161.

It is an arithmetic number, because the mean of its divisors is an integer number (503455353916).

Almost surely, 22013100130131 is an apocalyptic number.

2013100130131 is a deficient number, since it is larger than the sum of its proper divisors (721285533).

2013100130131 is an equidigital number, since it uses as much as digits as its factorization.

2013100130131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 721285532.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 2013100130131 its reverse (1310310013102), we get a palindrome (3323410143233).

The spelling of 2013100130131 in words is "two trillion, thirteen billion, one hundred million, one hundred thirty thousand, one hundred thirty-one".

Divisors: 1 2791 721282741 2013100130131