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2013100210001 = 2387526096087
BaseRepresentation
bin11101010010110110000…
…111110111011101010001
321010110011102012110201002
4131102312013313131101
5230440312123210001
64140445551551345
7265304333311106
oct35226607673521
97113142173632
102013100210001
11706829650521
1228619b22b555
13117ab062131a
146d612662aad
153757312646b
hex1d4b61f7751

2013100210001 has 4 divisors (see below), whose sum is σ = 2100626306112. Its totient is φ = 1925574113892.

The previous prime is 2013100209973. The next prime is 2013100210039. The reversal of 2013100210001 is 1000120013102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2013100210001 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2013100210201) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43763048021 + ... + 43763048066.

It is an arithmetic number, because the mean of its divisors is an integer number (525156576528).

Almost surely, 22013100210001 is an apocalyptic number.

It is an amenable number.

2013100210001 is a deficient number, since it is larger than the sum of its proper divisors (87526096111).

2013100210001 is an equidigital number, since it uses as much as digits as its factorization.

2013100210001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 87526096110.

The product of its (nonzero) digits is 12, while the sum is 11.

Adding to 2013100210001 its reverse (1000120013102), we get a palindrome (3013220223103).

The spelling of 2013100210001 in words is "two trillion, thirteen billion, one hundred million, two hundred ten thousand, one".

Divisors: 1 23 87526096087 2013100210001