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201310310011 = 1511333180861
BaseRepresentation
bin1011101101111100000…
…1111000111001111011
3201020121122212022220211
42323133001320321323
511244240414410021
6232251454331551
720354441254546
oct2733701707173
9636548768824
10201310310011
1178414470538
12330224b9bb7
1315ca2926b45
149a5a12785d
1553834ee3e1
hex2edf078e7b

201310310011 has 4 divisors (see below), whose sum is σ = 202643491024. Its totient is φ = 199977129000.

The previous prime is 201310309999. The next prime is 201310310021. The reversal of 201310310011 is 110013013102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 201310310011 - 225 = 201276755579 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 201310309973 and 201310310000.

It is not an unprimeable number, because it can be changed into a prime (201310310021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 666590280 + ... + 666590581.

It is an arithmetic number, because the mean of its divisors is an integer number (50660872756).

Almost surely, 2201310310011 is an apocalyptic number.

201310310011 is a deficient number, since it is larger than the sum of its proper divisors (1333181013).

201310310011 is a wasteful number, since it uses less digits than its factorization.

201310310011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1333181012.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 201310310011 its reverse (110013013102), we get a palindrome (311323323113).

The spelling of 201310310011 in words is "two hundred one billion, three hundred ten million, three hundred ten thousand, eleven".

Divisors: 1 151 1333180861 201310310011