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2013110010201 = 31597694200043
BaseRepresentation
bin11101010010110110101…
…101010000000101011001
321010110012002122101001110
4131102312231100011121
5230440322130311301
64140450542010533
7265304512516113
oct35226655200531
97113162571043
102013110010201
11706834134564
122861a2576a49
13117ab2672c64
146d613a943b3
1537573e100d6
hex1d4b6b50159

2013110010201 has 8 divisors (see below), whose sum is σ = 2684164119520. Its totient is φ = 1342064620512.

The previous prime is 2013110010169. The next prime is 2013110010229. The reversal of 2013110010201 is 1020100113102.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 2013110010201 - 25 = 2013110010169 is a prime.

It is a super-2 number, since 2×20131100102012 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2013110010701) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1620715 + ... + 2579328.

It is an arithmetic number, because the mean of its divisors is an integer number (335520514940).

Almost surely, 22013110010201 is an apocalyptic number.

It is an amenable number.

2013110010201 is a deficient number, since it is larger than the sum of its proper divisors (671054109319).

2013110010201 is a wasteful number, since it uses less digits than its factorization.

2013110010201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4359815.

The product of its (nonzero) digits is 12, while the sum is 12.

Adding to 2013110010201 its reverse (1020100113102), we get a palindrome (3033210123303).

The spelling of 2013110010201 in words is "two trillion, thirteen billion, one hundred ten million, ten thousand, two hundred one".

Divisors: 1 3 159769 479307 4200043 12600129 671036670067 2013110010201