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20131101433 = 67792969627
BaseRepresentation
bin10010101111111010…
…000011101011111001
31220221222012220121101
4102233322003223321
5312212030221213
613125331211401
71311603352552
oct225772035371
956858186541
1020131101433
1185a0533513
123a99a46b61
131b8a8ba851
14d8d891329
157cc515bdd
hex4afe83af9

20131101433 has 4 divisors (see below), whose sum is σ = 20134077840. Its totient is φ = 20128125028.

The previous prime is 20131101413. The next prime is 20131101437. The reversal of 20131101433 is 33410113102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20131101433 - 25 = 20131101401 is a prime.

It is a super-2 number, since 2×201311014332 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 20131101433.

It is not an unprimeable number, because it can be changed into a prime (20131101437) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1478035 + ... + 1491592.

It is an arithmetic number, because the mean of its divisors is an integer number (5033519460).

Almost surely, 220131101433 is an apocalyptic number.

It is an amenable number.

20131101433 is a deficient number, since it is larger than the sum of its proper divisors (2976407).

20131101433 is an equidigital number, since it uses as much as digits as its factorization.

20131101433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2976406.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 20131101433 its reverse (33410113102), we get a palindrome (53541214535).

The spelling of 20131101433 in words is "twenty billion, one hundred thirty-one million, one hundred one thousand, four hundred thirty-three".

Divisors: 1 6779 2969627 20131101433