Base | Representation |
---|---|
bin | 1001001001111001010101… |
… | …10100000010001110100001 |
3 | 2122021112020000212020010100 |
4 | 10210330222310002032201 |
5 | 10114312224340000113 |
6 | 110452054232253013 |
7 | 4145301434433105 |
oct | 444745264021641 |
9 | 78245200766110 |
10 | 20131230000033 |
11 | 6461674573419 |
12 | 2311698241169 |
13 | b3049cc54a29 |
14 | 4d84dcc25905 |
15 | 24d9d5badd73 |
hex | 124f2ad023a1 |
20131230000033 has 12 divisors (see below), whose sum is σ = 29081059151508. Its totient is φ = 13419612699360.
The previous prime is 20131229999987. The next prime is 20131230000097. The reversal of 20131230000033 is 33000003213102.
20131230000033 is a `hidden beast` number, since 20 + 1 + 312 + 300 + 0 + 0 + 0 + 33 = 666.
It can be written as a sum of positive squares in 2 ways, for example, as 8026070313024 + 12105159687009 = 2833032^2 + 3479247^2 .
It is not a de Polignac number, because 20131230000033 - 210 = 20131229999009 is a prime.
It is a super-2 number, since 2×201312300000332 (a number of 27 digits) contains 22 as substring.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 20131229999970 and 20131230000015.
It is not an unprimeable number, because it can be changed into a prime (20131230700033) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 100502778 + ... + 100702883.
It is an arithmetic number, because the mean of its divisors is an integer number (2423421595959).
Almost surely, 220131230000033 is an apocalyptic number.
It is an amenable number.
20131230000033 is a deficient number, since it is larger than the sum of its proper divisors (8949829151475).
20131230000033 is a wasteful number, since it uses less digits than its factorization.
20131230000033 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 201216784 (or 201216781 counting only the distinct ones).
The product of its (nonzero) digits is 324, while the sum is 18.
Adding to 20131230000033 its reverse (33000003213102), we get a palindrome (53131233213135).
The spelling of 20131230000033 in words is "twenty trillion, one hundred thirty-one billion, two hundred thirty million, thirty-three", and thus it is an aban number.
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