Search a number
-
+
20131303131001 = 43399463865599
BaseRepresentation
bin1001001001111001011110…
…01011000000011101111001
32122021112102010110122221201
410210330233023000131321
510114312402100143001
6110452105403534201
74145303313146656
oct444745713003571
978245363418851
1020131303131001
116461701882837
1223116b882a361
13b304b214b6aa
144d8508820c2d
1524d9dc307501
hex124f2f2c0779

20131303131001 has 4 divisors (see below), whose sum is σ = 20131767040000. Its totient is φ = 20130839222004.

The previous prime is 20131303130971. The next prime is 20131303131031. The reversal of 20131303131001 is 10013130313102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (20131303130971) and next prime (20131303131031).

It is a cyclic number.

It is not a de Polignac number, because 20131303131001 - 229 = 20130766260089 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 20131303131001.

It is not an unprimeable number, because it can be changed into a prime (20131303131031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 231889401 + ... + 231976198.

It is an arithmetic number, because the mean of its divisors is an integer number (5032941760000).

Almost surely, 220131303131001 is an apocalyptic number.

It is an amenable number.

20131303131001 is a deficient number, since it is larger than the sum of its proper divisors (463908999).

20131303131001 is an equidigital number, since it uses as much as digits as its factorization.

20131303131001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 463908998.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 20131303131001 its reverse (10013130313102), we get a palindrome (30144433444103).

The spelling of 20131303131001 in words is "twenty trillion, one hundred thirty-one billion, three hundred three million, one hundred thirty-one thousand, one".

Divisors: 1 43399 463865599 20131303131001