Base | Representation |
---|---|
bin | 11101010010110111111… |
… | …101010100110010101001 |
3 | 21010110020120010211000111 |
4 | 131102313331110302221 |
5 | 230440343014013001 |
6 | 4140453011534321 |
7 | 265305156112561 |
oct | 35226775246251 |
9 | 7113216124014 |
10 | 2013131001001 |
11 | 706844a7122a |
12 | 2861a95ba3a1 |
13 | 117ab6b12353 |
14 | 6d616799da1 |
15 | 37575ba9851 |
hex | 1d4b7f54ca9 |
2013131001001 has 4 divisors (see below), whose sum is σ = 2067539947012. Its totient is φ = 1958722054992.
The previous prime is 2013131000981. The next prime is 2013131001019. The reversal of 2013131001001 is 1001001313102.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 850777485376 + 1162353515625 = 922376^2 + 1078125^2 .
It is a cyclic number.
It is not a de Polignac number, because 2013131001001 - 213 = 2013130992809 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2013131001071) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27204472950 + ... + 27204473023.
It is an arithmetic number, because the mean of its divisors is an integer number (516884986753).
Almost surely, 22013131001001 is an apocalyptic number.
It is an amenable number.
2013131001001 is a deficient number, since it is larger than the sum of its proper divisors (54408946011).
2013131001001 is an equidigital number, since it uses as much as digits as its factorization.
2013131001001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 54408946010.
The product of its (nonzero) digits is 18, while the sum is 13.
Adding to 2013131001001 its reverse (1001001313102), we get a palindrome (3014132314103).
The spelling of 2013131001001 in words is "two trillion, thirteen billion, one hundred thirty-one million, one thousand, one".
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