Base | Representation |
---|---|
bin | 101101110001011111011100… |
… | …101010011110101011100011 |
3 | 222101210100100001202122100120 |
4 | 231301133130222132223203 |
5 | 202341303224222112201 |
6 | 1552053545025051323 |
7 | 60255251432314062 |
oct | 5561373452365343 |
9 | 871710301678316 |
10 | 201313114254051 |
11 | 59165459857728 |
12 | 1a6b39b6786b43 |
13 | 884398c31c757 |
14 | 379d86cb9a1d9 |
15 | 1841939484536 |
hex | b717dca9eae3 |
201313114254051 has 16 divisors (see below), whose sum is σ = 268516244937600. Its totient is φ = 134159371956608.
The previous prime is 201313114254041. The next prime is 201313114254071. The reversal of 201313114254051 is 150452411313102.
It is a cyclic number.
It is not a de Polignac number, because 201313114254051 - 26 = 201313114253987 is a prime.
It is not an unprimeable number, because it can be changed into a prime (201313114254011) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 91383835 + ... + 93560843.
It is an arithmetic number, because the mean of its divisors is an integer number (16782265308600).
Almost surely, 2201313114254051 is an apocalyptic number.
201313114254051 is a deficient number, since it is larger than the sum of its proper divisors (67203130683549).
201313114254051 is a wasteful number, since it uses less digits than its factorization.
201313114254051 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2188338.
The product of its (nonzero) digits is 14400, while the sum is 33.
Adding to 201313114254051 its reverse (150452411313102), we get a palindrome (351765525567153).
The spelling of 201313114254051 in words is "two hundred one trillion, three hundred thirteen billion, one hundred fourteen million, two hundred fifty-four thousand, fifty-one".
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