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201313232113 = 728759033159
BaseRepresentation
bin1011101101111100110…
…1000010010011110001
3201020121212100210021211
42323133031002103301
511244242141411423
6232252041120121
720354505145030
oct2733715022361
9636555323254
10201313232113
11784160869a4
1233023489041
1315ca340abb6
149a5a688717
1553838ca10d
hex2edf3424f1

201313232113 has 4 divisors (see below), whose sum is σ = 230072265280. Its totient is φ = 172554198948.

The previous prime is 201313232101. The next prime is 201313232117. The reversal of 201313232113 is 311232313102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-201313232113 is a prime.

It is a super-2 number, since 2×2013132321132 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (201313232117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14379516573 + ... + 14379516586.

It is an arithmetic number, because the mean of its divisors is an integer number (57518066320).

Almost surely, 2201313232113 is an apocalyptic number.

It is an amenable number.

201313232113 is a deficient number, since it is larger than the sum of its proper divisors (28759033167).

201313232113 is an equidigital number, since it uses as much as digits as its factorization.

201313232113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 28759033166.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 201313232113 its reverse (311232313102), we get a palindrome (512545545215).

The spelling of 201313232113 in words is "two hundred one billion, three hundred thirteen million, two hundred thirty-two thousand, one hundred thirteen".

Divisors: 1 7 28759033159 201313232113