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2013133000033 = 3559565645687
BaseRepresentation
bin11101010010111000000…
…100111100110101100001
321010110020200220101011201
4131102320010330311201
5230440344022000113
64140453122441201
7265305212106631
oct35227004746541
97113220811151
102013133000033
11706846107121
122861aa203201
13117ab73621cc
146d616b5a6c1
1537575e51cdd
hex1d4b813cd61

2013133000033 has 4 divisors (see below), whose sum is σ = 2013698649280. Its totient is φ = 2012567350788.

The previous prime is 2013133000009. The next prime is 2013133000091. The reversal of 2013133000033 is 3300003313102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2013133000033 - 237 = 1875694046561 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2013133000003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 282819285 + ... + 282826402.

It is an arithmetic number, because the mean of its divisors is an integer number (503424662320).

Almost surely, 22013133000033 is an apocalyptic number.

It is an amenable number.

2013133000033 is a deficient number, since it is larger than the sum of its proper divisors (565649247).

2013133000033 is an equidigital number, since it uses as much as digits as its factorization.

2013133000033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 565649246.

The product of its (nonzero) digits is 486, while the sum is 19.

Adding to 2013133000033 its reverse (3300003313102), we get a palindrome (5313136313135).

The spelling of 2013133000033 in words is "two trillion, thirteen billion, one hundred thirty-three million, thirty-three", and thus it is an aban number.

Divisors: 1 3559 565645687 2013133000033