201313331111043 has 40 divisors (see below), whose sum is σ = 313205159219040. Its totient is φ = 128742442295040.

The previous prime is 201313331111033. The next prime is 201313331111069. The reversal of 201313331111043 is 340111133313102.

201313331111043 is a `hidden beast` number, since 2 + 0 + 1 + 313 + 331 + 1 + 1 + 10 + 4 + 3 = 666.

It is not a de Polignac number, because 201313331111043 - 2²⁴ = 201313314333827 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a junction number, because it is equal to n+sod(n) for n = 201313331110998 and 201313331111016.

It is not an unprimeable number, because it can be changed into a prime (201313331111033) by changing a digit.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 472826758 + ... + 473252331.

It is an arithmetic number, because the mean of its divisors is an integer number (7830128980476).

Almost surely, 2^{201313331111043} is an apocalyptic number.

201313331111043 is a deficient number, since it is larger than the sum of its proper divisors (111891828107997).

201313331111043 is an equidigital number, since it uses as much as digits as its factorization.

201313331111043 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 946079209 (or 946079200 counting only the distinct ones).

The product of its (nonzero) digits is 1944, while the sum is 27.

Adding to 201313331111043 its reverse (340111133313102), we get a palindrome (541424464424145).

The spelling of 201313331111043 in words is "two hundred one trillion, three hundred thirteen billion, three hundred thirty-one million, one hundred eleven thousand, forty-three".