Base | Representation |
---|---|
bin | 101101110001100000010111… |
… | …011011101100000010011001 |
3 | 222101210102212210001112022011 |
4 | 231301200113123230002121 |
5 | 202341312234124413340 |
6 | 1552054230530025521 |
7 | 60255315034065262 |
oct | 5561402733540231 |
9 | 871712783045264 |
10 | 201314100232345 |
11 | 59165915373821 |
12 | 1a6b4030a182a1 |
13 | 8843ab868a669 |
14 | 379d923ad7969 |
15 | 1841995ce60ea |
hex | b718176ec099 |
201314100232345 has 8 divisors (see below), whose sum is σ = 241585162306560. Its totient is φ = 161045785500720.
The previous prime is 201314100232321. The next prime is 201314100232367. The reversal of 201314100232345 is 543232001413102.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 201314100232345 - 25 = 201314100232313 is a prime.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 686674435 + ... + 686967544.
It is an arithmetic number, because the mean of its divisors is an integer number (30198145288320).
Almost surely, 2201314100232345 is an apocalyptic number.
It is an amenable number.
201314100232345 is a deficient number, since it is larger than the sum of its proper divisors (40271062074215).
201314100232345 is a wasteful number, since it uses less digits than its factorization.
201314100232345 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1373671295.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 201314100232345 its reverse (543232001413102), we get a palindrome (744546101645447).
The spelling of 201314100232345 in words is "two hundred one trillion, three hundred fourteen billion, one hundred million, two hundred thirty-two thousand, three hundred forty-five".
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