Base | Representation |
---|---|
bin | 10010101111111101… |
… | …100100001111011011 |
3 | 1220222000221122022020 |
4 | 102233331210033123 |
5 | 312212244134321 |
6 | 13125403025523 |
7 | 1311614233251 |
oct | 225775441733 |
9 | 56860848266 |
10 | 20132021211 |
11 | 85a1001565 |
12 | 3a9a20b2a3 |
13 | 1b8ab503b3 |
14 | d8da505d1 |
15 | 7cc6484c6 |
hex | 4aff643db |
20132021211 has 4 divisors (see below), whose sum is σ = 26842694952. Its totient is φ = 13421347472.
The previous prime is 20132021179. The next prime is 20132021213. The reversal of 20132021211 is 11212023102.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 20132021211 - 25 = 20132021179 is a prime.
It is not an unprimeable number, because it can be changed into a prime (20132021213) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3355336866 + ... + 3355336871.
It is an arithmetic number, because the mean of its divisors is an integer number (6710673738).
Almost surely, 220132021211 is an apocalyptic number.
20132021211 is a deficient number, since it is larger than the sum of its proper divisors (6710673741).
20132021211 is an equidigital number, since it uses as much as digits as its factorization.
20132021211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6710673740.
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 20132021211 its reverse (11212023102), we get a palindrome (31344044313).
The spelling of 20132021211 in words is "twenty billion, one hundred thirty-two million, twenty-one thousand, two hundred eleven".
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