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20132033113 = 31649420423
BaseRepresentation
bin10010101111111101…
…100111001001011001
31220222000222020122001
4102233331213021121
5312212300024423
613125403201001
71311614313043
oct225775471131
956860866561
1020132033113
1185a100a4a5
123a9a216161
131b8ab5593a
14d8da54a93
157cc64bcad
hex4aff67259

20132033113 has 4 divisors (see below), whose sum is σ = 20781453568. Its totient is φ = 19482612660.

The previous prime is 20132033081. The next prime is 20132033137. The reversal of 20132033113 is 31133023102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20132033113 - 25 = 20132033081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (20132033143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 324710181 + ... + 324710242.

It is an arithmetic number, because the mean of its divisors is an integer number (5195363392).

Almost surely, 220132033113 is an apocalyptic number.

It is an amenable number.

20132033113 is a deficient number, since it is larger than the sum of its proper divisors (649420455).

20132033113 is an equidigital number, since it uses as much as digits as its factorization.

20132033113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 649420454.

The product of its (nonzero) digits is 324, while the sum is 19.

Adding to 20132033113 its reverse (31133023102), we get a palindrome (51265056215).

The spelling of 20132033113 in words is "twenty billion, one hundred thirty-two million, thirty-three thousand, one hundred thirteen".

Divisors: 1 31 649420423 20132033113