20132200204121 has 4 divisors (see below), whose sum is σ = 20415752319744. Its totient is φ = 19848648088500.

The previous prime is 20132200204117. The next prime is 20132200204133. The reversal of 20132200204121 is 12140200223102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20132200204121 - 2² = 20132200204117 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 20132200204093 and 20132200204102.

It is not an unprimeable number, because it can be changed into a prime (20132200204141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 141776057705 + ... + 141776057846.

It is an arithmetic number, because the mean of its divisors is an integer number (5103938079936).

Almost surely, 2^{20132200204121} is an apocalyptic number.

It is an amenable number.

20132200204121 is a deficient number, since it is larger than the sum of its proper divisors (283552115623).

20132200204121 is an equidigital number, since it uses as much as digits as its factorization.

20132200204121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 283552115622.

The product of its (nonzero) digits is 384, while the sum is 20.

Adding to 20132200204121 its reverse (12140200223102), we get a palindrome (32272400427223).

The spelling of 20132200204121 in words is "twenty trillion, one hundred thirty-two billion, two hundred million, two hundred four thousand, one hundred twenty-one".