Base | Representation |
---|---|
bin | 11101010010111110011… |
… | …101101000101100000011 |
3 | 21010110112011111100220100 |
4 | 131102332131220230003 |
5 | 230441103433300103 |
6 | 4140511511013443 |
7 | 265310652535011 |
oct | 35227635505403 |
9 | 7113464440810 |
10 | 2013240134403 |
11 | 7068a0630823 |
12 | 28621a06a283 |
13 | 117b03603124 |
14 | 6d6270878b1 |
15 | 375805655a3 |
hex | 1d4be768b03 |
2013240134403 has 12 divisors (see below), whose sum is σ = 3079073146968. Its totient is φ = 1263209496000.
The previous prime is 2013240134401. The next prime is 2013240134461. The reversal of 2013240134403 is 3044310423102.
2013240134403 is a `hidden beast` number, since 2 + 0 + 1 + 3 + 240 + 13 + 4 + 403 = 666.
It is not a de Polignac number, because 2013240134403 - 21 = 2013240134401 is a prime.
It is not an unprimeable number, because it can be changed into a prime (2013240134401) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 6579215973 + ... + 6579216278.
It is an arithmetic number, because the mean of its divisors is an integer number (256589428914).
Almost surely, 22013240134403 is an apocalyptic number.
2013240134403 is a deficient number, since it is larger than the sum of its proper divisors (1065833012565).
2013240134403 is a wasteful number, since it uses less digits than its factorization.
2013240134403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13158432274 (or 13158432271 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 27.
Adding to 2013240134403 its reverse (3044310423102), we get a palindrome (5057550557505).
The spelling of 2013240134403 in words is "two trillion, thirteen billion, two hundred forty million, one hundred thirty-four thousand, four hundred three".
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