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2013240134403 = 321713158432251
BaseRepresentation
bin11101010010111110011…
…101101000101100000011
321010110112011111100220100
4131102332131220230003
5230441103433300103
64140511511013443
7265310652535011
oct35227635505403
97113464440810
102013240134403
117068a0630823
1228621a06a283
13117b03603124
146d6270878b1
15375805655a3
hex1d4be768b03

2013240134403 has 12 divisors (see below), whose sum is σ = 3079073146968. Its totient is φ = 1263209496000.

The previous prime is 2013240134401. The next prime is 2013240134461. The reversal of 2013240134403 is 3044310423102.

2013240134403 is a `hidden beast` number, since 2 + 0 + 1 + 3 + 240 + 13 + 4 + 403 = 666.

It is not a de Polignac number, because 2013240134403 - 21 = 2013240134401 is a prime.

It is not an unprimeable number, because it can be changed into a prime (2013240134401) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 6579215973 + ... + 6579216278.

It is an arithmetic number, because the mean of its divisors is an integer number (256589428914).

Almost surely, 22013240134403 is an apocalyptic number.

2013240134403 is a deficient number, since it is larger than the sum of its proper divisors (1065833012565).

2013240134403 is a wasteful number, since it uses less digits than its factorization.

2013240134403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13158432274 (or 13158432271 counting only the distinct ones).

The product of its (nonzero) digits is 6912, while the sum is 27.

Adding to 2013240134403 its reverse (3044310423102), we get a palindrome (5057550557505).

The spelling of 2013240134403 in words is "two trillion, thirteen billion, two hundred forty million, one hundred thirty-four thousand, four hundred three".

Divisors: 1 3 9 17 51 153 13158432251 39475296753 118425890259 223693348267 671080044801 2013240134403