Search a number
-
+
2013310322321 = 5473680640443
BaseRepresentation
bin11101010011000010101…
…001011000011010010001
321010110201001120021121212
4131103002221120122101
5230441224420303241
64140522455225505
7265312464243344
oct35230251303221
97113631507555
102013310322321
1170692720aa71
12286239678295
13117b1500933c
146d63251845b
15375867cbbeb
hex1d4c2a58691

2013310322321 has 4 divisors (see below), whose sum is σ = 2016990963312. Its totient is φ = 2009629681332.

The previous prime is 2013310322299. The next prime is 2013310322327. The reversal of 2013310322321 is 1232230133102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2013310322321 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (2013310322327) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1840319675 + ... + 1840320768.

It is an arithmetic number, because the mean of its divisors is an integer number (504247740828).

Almost surely, 22013310322321 is an apocalyptic number.

It is an amenable number.

2013310322321 is a deficient number, since it is larger than the sum of its proper divisors (3680640991).

2013310322321 is an equidigital number, since it uses as much as digits as its factorization.

2013310322321 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3680640990.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 2013310322321 its reverse (1232230133102), we get a palindrome (3245540455423).

The spelling of 2013310322321 in words is "two trillion, thirteen billion, three hundred ten million, three hundred twenty-two thousand, three hundred twenty-one".

Divisors: 1 547 3680640443 2013310322321