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20133121023433 = 111830283729403
BaseRepresentation
bin1001001001111100110111…
…00001101101110111001001
32122021201002211011011120001
410210332123201231313021
510114330112440222213
6110453010023403001
74145366336034625
oct444763341556711
978251084134501
1020133121023433
116462454a48280
122311b255b3461
13b307119647a2
144d863c034185
1524da96be71dd
hex124f9b86ddc9

20133121023433 has 4 divisors (see below), whose sum is σ = 21963404752848. Its totient is φ = 18302837294020.

The previous prime is 20133121023403. The next prime is 20133121023451. The reversal of 20133121023433 is 33432012133102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20133121023433 - 241 = 17934097767881 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (20133121023403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 915141864691 + ... + 915141864712.

It is an arithmetic number, because the mean of its divisors is an integer number (5490851188212).

Almost surely, 220133121023433 is an apocalyptic number.

It is an amenable number.

20133121023433 is a deficient number, since it is larger than the sum of its proper divisors (1830283729415).

20133121023433 is a wasteful number, since it uses less digits than its factorization.

20133121023433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1830283729414.

The product of its (nonzero) digits is 7776, while the sum is 28.

Adding to 20133121023433 its reverse (33432012133102), we get a palindrome (53565133156535).

The spelling of 20133121023433 in words is "twenty trillion, one hundred thirty-three billion, one hundred twenty-one million, twenty-three thousand, four hundred thirty-three".

Divisors: 1 11 1830283729403 20133121023433