Base | Representation |
---|---|
bin | 11101010011000010110… |
… | …111110111100111000011 |
3 | 21010110201022201020020111 |
4 | 131103002313313213003 |
5 | 230441231403321011 |
6 | 4140523112452151 |
7 | 265312541441566 |
oct | 35230267674703 |
9 | 7113638636214 |
10 | 2013314120131 |
11 | 706929374356 |
12 | 28623a9aa057 |
13 | 117b15a38b72 |
14 | 6d632c264dd |
15 | 37586ccc121 |
hex | 1d4c2df79c3 |
2013314120131 has 4 divisors (see below), whose sum is σ = 2014565404600. Its totient is φ = 2012062835664.
The previous prime is 2013314120117. The next prime is 2013314120141. The reversal of 2013314120131 is 1310214133102.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2013314120131 - 27 = 2013314120003 is a prime.
It is a super-2 number, since 2×20133141201312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2013314120141) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 625639821 + ... + 625643038.
It is an arithmetic number, because the mean of its divisors is an integer number (503641351150).
Almost surely, 22013314120131 is an apocalyptic number.
2013314120131 is a deficient number, since it is larger than the sum of its proper divisors (1251284469).
2013314120131 is a wasteful number, since it uses less digits than its factorization.
2013314120131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1251284468.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 2013314120131 its reverse (1310214133102), we get a palindrome (3323528253233).
The spelling of 2013314120131 in words is "two trillion, thirteen billion, three hundred fourteen million, one hundred twenty thousand, one hundred thirty-one".
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