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20133340041 = 36711113347
BaseRepresentation
bin10010110000000010…
…100110001110001001
31220222010102122101210
4102300002212032021
5312213113340131
613125451203333
71311631365243
oct226002461611
956863378353
1020133340041
1185a1822401
123a9a746549
131b8b1c2779
14d8dcb5093
157cc809146
hex4b00a6389

20133340041 has 4 divisors (see below), whose sum is σ = 26844453392. Its totient is φ = 13422226692.

The previous prime is 20133340033. The next prime is 20133340043. The reversal of 20133340041 is 14004333102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 20133340041 - 23 = 20133340033 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (20133340043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3355556671 + ... + 3355556676.

It is an arithmetic number, because the mean of its divisors is an integer number (6711113348).

Almost surely, 220133340041 is an apocalyptic number.

It is an amenable number.

20133340041 is a deficient number, since it is larger than the sum of its proper divisors (6711113351).

20133340041 is an equidigital number, since it uses as much as digits as its factorization.

20133340041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6711113350.

The product of its (nonzero) digits is 864, while the sum is 21.

Adding to 20133340041 its reverse (14004333102), we get a palindrome (34137673143).

The spelling of 20133340041 in words is "twenty billion, one hundred thirty-three million, three hundred forty thousand, forty-one".

Divisors: 1 3 6711113347 20133340041