Base | Representation |
---|---|
bin | 1001001001111101110111… |
… | …01100110110010010011001 |
3 | 2122021202111102212021212112 |
4 | 10210332323230312102121 |
5 | 10114332214131444231 |
6 | 110453135345122105 |
7 | 4145415612130541 |
oct | 444767354662231 |
9 | 78252442767775 |
10 | 20133660812441 |
11 | 64627017107a0 |
12 | 2312056329335 |
13 | b3079973b377 |
14 | 4d868d9c6321 |
15 | 24dac92be92b |
hex | 124fbbb36499 |
20133660812441 has 4 divisors (see below), whose sum is σ = 21963993613584. Its totient is φ = 18303328011300.
The previous prime is 20133660812407. The next prime is 20133660812467. The reversal of 20133660812441 is 14421806633102.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 20133660812441 - 238 = 19858782905497 is a prime.
It is not an unprimeable number, because it can be changed into a prime (20133660812141) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 915166400555 + ... + 915166400576.
It is an arithmetic number, because the mean of its divisors is an integer number (5490998403396).
Almost surely, 220133660812441 is an apocalyptic number.
It is an amenable number.
20133660812441 is a deficient number, since it is larger than the sum of its proper divisors (1830332801143).
20133660812441 is a wasteful number, since it uses less digits than its factorization.
20133660812441 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1830332801142.
The product of its (nonzero) digits is 165888, while the sum is 41.
The spelling of 20133660812441 in words is "twenty trillion, one hundred thirty-three billion, six hundred sixty million, eight hundred twelve thousand, four hundred forty-one".
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