Base | Representation |
---|---|
bin | 11101010011001000001… |
… | …110101110111111110011 |
3 | 21010110221120211121120112 |
4 | 131103020032232333303 |
5 | 230441422411001433 |
6 | 4140540043131535 |
7 | 265315012424666 |
oct | 35231016567763 |
9 | 7113846747515 |
10 | 2013404000243 |
11 | 706975083639 |
12 | 286264b13bab |
13 | 117b2b54836c |
14 | 6d640b416dd |
15 | 3758eb33348 |
hex | 1d4c83aeff3 |
2013404000243 has 4 divisors (see below), whose sum is σ = 2037661879848. Its totient is φ = 1989146120640.
The previous prime is 2013404000207. The next prime is 2013404000261. The reversal of 2013404000243 is 3420004043102.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2013404000243 - 222 = 2013399805939 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2013404003243) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12128939678 + ... + 12128939843.
It is an arithmetic number, because the mean of its divisors is an integer number (509415469962).
Almost surely, 22013404000243 is an apocalyptic number.
2013404000243 is a deficient number, since it is larger than the sum of its proper divisors (24257879605).
2013404000243 is an equidigital number, since it uses as much as digits as its factorization.
2013404000243 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 24257879604.
The product of its (nonzero) digits is 2304, while the sum is 23.
Adding to 2013404000243 its reverse (3420004043102), we get a palindrome (5433408043345).
The spelling of 2013404000243 in words is "two trillion, thirteen billion, four hundred four million, two hundred forty-three", and thus it is an aban number.
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