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201341014211 = 741727145883
BaseRepresentation
bin1011101110000011011…
…1000001000011000011
3201020200210122021011102
42323200313001003003
511244321244423321
6232254512405015
720355263245301
oct2734067010303
9636623567142
10201341014211
117842a832007
123303084676b
1315ca90b74cc
149a6023b271
155386066c0b
hex2ee0dc10c3

201341014211 has 4 divisors (see below), whose sum is σ = 201368167512. Its totient is φ = 201313860912.

The previous prime is 201341014129. The next prime is 201341014219. The reversal of 201341014211 is 112410143102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 201341014211 - 214 = 201340997827 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (201341014219) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13565525 + ... + 13580358.

It is an arithmetic number, because the mean of its divisors is an integer number (50342041878).

Almost surely, 2201341014211 is an apocalyptic number.

201341014211 is a deficient number, since it is larger than the sum of its proper divisors (27153301).

201341014211 is an equidigital number, since it uses as much as digits as its factorization.

201341014211 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 27153300.

The product of its (nonzero) digits is 192, while the sum is 20.

Adding to 201341014211 its reverse (112410143102), we get a palindrome (313751157313).

The spelling of 201341014211 in words is "two hundred one billion, three hundred forty-one million, fourteen thousand, two hundred eleven".

Divisors: 1 7417 27145883 201341014211